Optimal. Leaf size=262 \[ \frac {(5 A b+3 a B) \sqrt {x}}{64 a^3 b^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(A b-a B) x^{3/2}}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(5 A b+3 a B) \sqrt {x}}{24 a b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(5 A b+3 a B) \sqrt {x}}{96 a^2 b^2 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(5 A b+3 a B) (a+b x) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{64 a^{7/2} b^{5/2} \sqrt {a^2+2 a b x+b^2 x^2}} \]
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Rubi [A]
time = 0.10, antiderivative size = 262, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 6, integrand size = 31, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.194, Rules used = {784, 79, 43, 44,
65, 211} \begin {gather*} \frac {\sqrt {x} (3 a B+5 A b)}{96 a^2 b^2 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {\sqrt {x} (3 a B+5 A b)}{24 a b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {x^{3/2} (A b-a B)}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(a+b x) (3 a B+5 A b) \text {ArcTan}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{64 a^{7/2} b^{5/2} \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\sqrt {x} (3 a B+5 A b)}{64 a^3 b^2 \sqrt {a^2+2 a b x+b^2 x^2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 43
Rule 44
Rule 65
Rule 79
Rule 211
Rule 784
Rubi steps
\begin {align*} \int \frac {\sqrt {x} (A+B x)}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx &=\frac {\left (b^4 \left (a b+b^2 x\right )\right ) \int \frac {\sqrt {x} (A+B x)}{\left (a b+b^2 x\right )^5} \, dx}{\sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {(A b-a B) x^{3/2}}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\left (b^2 (5 A b+3 a B) \left (a b+b^2 x\right )\right ) \int \frac {\sqrt {x}}{\left (a b+b^2 x\right )^4} \, dx}{8 a \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {(A b-a B) x^{3/2}}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(5 A b+3 a B) \sqrt {x}}{24 a b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\left ((5 A b+3 a B) \left (a b+b^2 x\right )\right ) \int \frac {1}{\sqrt {x} \left (a b+b^2 x\right )^3} \, dx}{48 a \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {(A b-a B) x^{3/2}}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(5 A b+3 a B) \sqrt {x}}{24 a b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(5 A b+3 a B) \sqrt {x}}{96 a^2 b^2 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\left ((5 A b+3 a B) \left (a b+b^2 x\right )\right ) \int \frac {1}{\sqrt {x} \left (a b+b^2 x\right )^2} \, dx}{64 a^2 b \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {(5 A b+3 a B) \sqrt {x}}{64 a^3 b^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(A b-a B) x^{3/2}}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(5 A b+3 a B) \sqrt {x}}{24 a b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(5 A b+3 a B) \sqrt {x}}{96 a^2 b^2 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\left ((5 A b+3 a B) \left (a b+b^2 x\right )\right ) \int \frac {1}{\sqrt {x} \left (a b+b^2 x\right )} \, dx}{128 a^3 b^2 \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {(5 A b+3 a B) \sqrt {x}}{64 a^3 b^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(A b-a B) x^{3/2}}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(5 A b+3 a B) \sqrt {x}}{24 a b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(5 A b+3 a B) \sqrt {x}}{96 a^2 b^2 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\left ((5 A b+3 a B) \left (a b+b^2 x\right )\right ) \text {Subst}\left (\int \frac {1}{a b+b^2 x^2} \, dx,x,\sqrt {x}\right )}{64 a^3 b^2 \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {(5 A b+3 a B) \sqrt {x}}{64 a^3 b^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(A b-a B) x^{3/2}}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(5 A b+3 a B) \sqrt {x}}{24 a b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(5 A b+3 a B) \sqrt {x}}{96 a^2 b^2 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(5 A b+3 a B) (a+b x) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{64 a^{7/2} b^{5/2} \sqrt {a^2+2 a b x+b^2 x^2}}\\ \end {align*}
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Mathematica [A]
time = 0.22, size = 146, normalized size = 0.56 \begin {gather*} \frac {\sqrt {a} \sqrt {b} \sqrt {x} \left (-9 a^4 B+15 A b^4 x^3+a b^3 x^2 (55 A+9 B x)-3 a^3 b (5 A+11 B x)+a^2 b^2 x (73 A+33 B x)\right )+3 (5 A b+3 a B) (a+b x)^4 \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{192 a^{7/2} b^{5/2} (a+b x)^3 \sqrt {(a+b x)^2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.65, size = 357, normalized size = 1.36
method | result | size |
default | \(\frac {\left (15 A \sqrt {a b}\, x^{\frac {7}{2}} b^{4}+9 B \sqrt {a b}\, x^{\frac {7}{2}} a \,b^{3}+55 A \sqrt {a b}\, x^{\frac {5}{2}} a \,b^{3}+15 A \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right ) b^{5} x^{4}+33 B \sqrt {a b}\, x^{\frac {5}{2}} a^{2} b^{2}+9 B \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right ) a \,b^{4} x^{4}+60 A \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right ) a \,b^{4} x^{3}+36 B \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right ) a^{2} b^{3} x^{3}+73 A \sqrt {a b}\, x^{\frac {3}{2}} a^{2} b^{2}+90 A \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right ) a^{2} b^{3} x^{2}-33 B \sqrt {a b}\, x^{\frac {3}{2}} a^{3} b +54 B \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right ) a^{3} b^{2} x^{2}+60 A \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right ) a^{3} b^{2} x +36 B \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right ) a^{4} b x -15 A \sqrt {a b}\, \sqrt {x}\, a^{3} b +15 A \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right ) a^{4} b -9 B \sqrt {a b}\, \sqrt {x}\, a^{4}+9 B \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right ) a^{5}\right ) \left (b x +a \right )}{192 \sqrt {a b}\, b^{2} a^{3} \left (\left (b x +a \right )^{2}\right )^{\frac {5}{2}}}\) | \(357\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 368 vs.
\(2 (179) = 358\).
time = 0.60, size = 368, normalized size = 1.40 \begin {gather*} -\frac {15 \, {\left ({\left (B a b^{5} + A b^{6}\right )} x^{2} - {\left (3 \, B a^{2} b^{4} + 7 \, A a b^{5}\right )} x\right )} x^{\frac {9}{2}} + 30 \, {\left ({\left (B a^{2} b^{4} + A a b^{5}\right )} x^{2} - 3 \, {\left (3 \, B a^{3} b^{3} + 7 \, A a^{2} b^{4}\right )} x\right )} x^{\frac {7}{2}} - 20 \, {\left (6 \, {\left (B a^{3} b^{3} + A a^{2} b^{4}\right )} x^{2} + 11 \, {\left (3 \, B a^{4} b^{2} + 7 \, A a^{3} b^{3}\right )} x\right )} x^{\frac {5}{2}} - 2 \, {\left (255 \, {\left (B a^{4} b^{2} + A a^{3} b^{3}\right )} x^{2} + 139 \, {\left (3 \, B a^{5} b + 7 \, A a^{4} b^{2}\right )} x\right )} x^{\frac {3}{2}} + {\left (3 \, {\left (3 \, B a^{5} b - 253 \, A a^{4} b^{2}\right )} x^{2} - 5 \, {\left (3 \, B a^{6} + 263 \, A a^{5} b\right )} x\right )} \sqrt {x}}{1920 \, {\left (a^{5} b^{6} x^{5} + 5 \, a^{6} b^{5} x^{4} + 10 \, a^{7} b^{4} x^{3} + 10 \, a^{8} b^{3} x^{2} + 5 \, a^{9} b^{2} x + a^{10} b\right )}} + \frac {{\left (3 \, B a + 5 \, A b\right )} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{64 \, \sqrt {a b} a^{3} b^{2}} + \frac {{\left (B a b + A b^{2}\right )} x^{\frac {3}{2}} - 2 \, {\left (3 \, B a^{2} + 5 \, A a b\right )} \sqrt {x}}{128 \, a^{5} b^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 3.91, size = 537, normalized size = 2.05 \begin {gather*} \left [-\frac {3 \, {\left (3 \, B a^{5} + 5 \, A a^{4} b + {\left (3 \, B a b^{4} + 5 \, A b^{5}\right )} x^{4} + 4 \, {\left (3 \, B a^{2} b^{3} + 5 \, A a b^{4}\right )} x^{3} + 6 \, {\left (3 \, B a^{3} b^{2} + 5 \, A a^{2} b^{3}\right )} x^{2} + 4 \, {\left (3 \, B a^{4} b + 5 \, A a^{3} b^{2}\right )} x\right )} \sqrt {-a b} \log \left (\frac {b x - a - 2 \, \sqrt {-a b} \sqrt {x}}{b x + a}\right ) + 2 \, {\left (9 \, B a^{5} b + 15 \, A a^{4} b^{2} - 3 \, {\left (3 \, B a^{2} b^{4} + 5 \, A a b^{5}\right )} x^{3} - 11 \, {\left (3 \, B a^{3} b^{3} + 5 \, A a^{2} b^{4}\right )} x^{2} + {\left (33 \, B a^{4} b^{2} - 73 \, A a^{3} b^{3}\right )} x\right )} \sqrt {x}}{384 \, {\left (a^{4} b^{7} x^{4} + 4 \, a^{5} b^{6} x^{3} + 6 \, a^{6} b^{5} x^{2} + 4 \, a^{7} b^{4} x + a^{8} b^{3}\right )}}, -\frac {3 \, {\left (3 \, B a^{5} + 5 \, A a^{4} b + {\left (3 \, B a b^{4} + 5 \, A b^{5}\right )} x^{4} + 4 \, {\left (3 \, B a^{2} b^{3} + 5 \, A a b^{4}\right )} x^{3} + 6 \, {\left (3 \, B a^{3} b^{2} + 5 \, A a^{2} b^{3}\right )} x^{2} + 4 \, {\left (3 \, B a^{4} b + 5 \, A a^{3} b^{2}\right )} x\right )} \sqrt {a b} \arctan \left (\frac {\sqrt {a b}}{b \sqrt {x}}\right ) + {\left (9 \, B a^{5} b + 15 \, A a^{4} b^{2} - 3 \, {\left (3 \, B a^{2} b^{4} + 5 \, A a b^{5}\right )} x^{3} - 11 \, {\left (3 \, B a^{3} b^{3} + 5 \, A a^{2} b^{4}\right )} x^{2} + {\left (33 \, B a^{4} b^{2} - 73 \, A a^{3} b^{3}\right )} x\right )} \sqrt {x}}{192 \, {\left (a^{4} b^{7} x^{4} + 4 \, a^{5} b^{6} x^{3} + 6 \, a^{6} b^{5} x^{2} + 4 \, a^{7} b^{4} x + a^{8} b^{3}\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sqrt {x} \left (A + B x\right )}{\left (\left (a + b x\right )^{2}\right )^{\frac {5}{2}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.78, size = 148, normalized size = 0.56 \begin {gather*} \frac {{\left (3 \, B a + 5 \, A b\right )} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{64 \, \sqrt {a b} a^{3} b^{2} \mathrm {sgn}\left (b x + a\right )} + \frac {9 \, B a b^{3} x^{\frac {7}{2}} + 15 \, A b^{4} x^{\frac {7}{2}} + 33 \, B a^{2} b^{2} x^{\frac {5}{2}} + 55 \, A a b^{3} x^{\frac {5}{2}} - 33 \, B a^{3} b x^{\frac {3}{2}} + 73 \, A a^{2} b^{2} x^{\frac {3}{2}} - 9 \, B a^{4} \sqrt {x} - 15 \, A a^{3} b \sqrt {x}}{192 \, {\left (b x + a\right )}^{4} a^{3} b^{2} \mathrm {sgn}\left (b x + a\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {\sqrt {x}\,\left (A+B\,x\right )}{{\left (a^2+2\,a\,b\,x+b^2\,x^2\right )}^{5/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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